Find the areas of the sectors formed by UTV.
161.97 square inches
151.97 square inches
150.97 square inches
147.97 square inches
plz ans fast
Answers
Answer:
you are giving vedantu VMast paper
- The areas of minor sector and major sector is equal to 39.08 inches² and 161.88 inches² respectively .
Given :-
- UT = VT = Radius of circle = 8 inches .
- ∠UTV = Angle at centre = 70°
To Find :- The areas of the sectors formed by UTV ?
Formula used :-
- Area of minor sector = (θ/360°)•πr² = (θ/360°) × Area of circle . { r = radius of circle, θ = angle at centre }
- Area of major sector = Area of circle - Area of minor sector .
Solution :-
given that,
→ Radius of circle = r = 8 inches
So,
→ Area of circle = πr²
→ Area of circle = 3.14 × 8 × 8
→ Area of circle = 200.96 inches² ---- Equation (1)
Then,
→ Area of minor sector = (θ/360°) × Area of circle
putting given value of θ as 70°,
→ Area of minor sector = (70°/360°) × Area of circle
→ Area of minor sector = (7/36) × Area of circle
putting value from Equation (1) in RHS now,
→ Area of minor sector = (7/36) × 200.96
→ Area of minor sector = 39.08 inches² ---- Equation (2)
therefore,
→ Area of major sector = Area of circle - Area of minor sector
subtracting Equation (2) from Equation (1),
→ Area of major sector = 200.96 - 39.08
→ Area of major sector = 161.88 inches²
Hence, areas of minor sector and major sector is equal to 39.08 inches² and 161.88 inches² respectively .
Learn more :-
In the given figure PQ || RS || BC. If RS = 4 cm, PQ = 3 cm, then BC is equal to https://brainly.in/question/45600047
Which of these can never be the ratio of the sides of the triangle? a. 3:5:7 b. 3:5:3 C. 2:2:3 d. 2:5:8
https://brainly.in/question/45357307