Question

find the areas of these triangle using the formula.​

Answer 1

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Hypotenuse:- 5cm

Base:- 4cm

Using Pythagorean theorem:-

5² = 4²+P²

25 - 16 = P²

9 = P²

√9 = √P²

P = 3cm

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Area of right angled ∆ :-

1\2 × 4 × 3

= 6cm²

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Answer 2

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Hypotenuse:- 5cmBase:- 4cmUsing Pythagorean theorem:-5² = 4²+P²25 - 16 = P²9 = P²√9 = √P²P = 3cm___________________

Area of right angled ∆ :-1\2 × 4 × 3= 6cm²