Question

find the areas of triangle whose vertices are A(2,-6) B(5,4) C(-2,4)​

Answer 1

Answer:

area of triangle is lx1(y2-y3)+de(y3-y1)+de(y1-y2)l

2(4-4)+5(4-(-6))+-2(-6-4)

2(0)+40+20

0+40+20

60

Answer 2

Step-by-step explanation:

$vertices \: of \: triangle \: are : \\ x_1=2, \: x_2=5, \: x_3=-2 \\ y_1=-6, \: y_2=4, \: y_3=4 \\ area \: of \: triangle = \frac{1}{2 } |x_1(y_2-y_3) + x_2(y_3-y_1)+x_3(y_1 - y_2)| \\ = \frac{1}{2} |2(4 - 4) + 5(4 - ( - 6)) + ( - 2)( - 6 - 4)| \\ = \frac{1}{2} |0 + 50 + 20| \\ = \frac{1}{2} \times 70 \\ = 35sq \: units$

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