Question

find the arena of a triangle whose vertices are(2,3),(-1,0),(2,-4)

Answer 1

Answer:

10.5 Square units

Step-by-step explanation:

Let the points be A(2,3), B(-1,0), C(2,-4)

Area of triangle ABC = 1/2 [x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]

Here  

X1=2, Y1=3

X2=-1,Y2=0

X3=2,Y3=-4

Substituting values, we get,

Area of triangle ABC = 1/2 [2(0-(-4))+(-1)(-4-3)+2(3-0)]

                    = 1/2 [2(4) + (-1)(-7) + 2(3)]

                    = 1/2 [8+7+6]

                    = 1/2 [21]

                     = 10.5 Square units.

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