Math, asked by avinash20, 1 year ago

find the arguement of i^i

Answers

Answered by bhagatpriyanshu1
4
Since i=0+i=cosπ2+i sinπ2=eiπ2⇒ii=(eiπ2)i=ei2π2=e−π2which is purely real.Thus argument of ii=0

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