Question

Find the argument of 1-i upon 1+i

Answer 1

Answer:

1-i/1+i = 1-i/1+i x 1-i/1-i=

(1-i)^2/(1-i^2) = 1-2i+i^2/1-(-1)=

1-1-2i/1+1= -2i/2

= -i = -√-1

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