Find the argument of (-√3-i)
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Step-by-step explanation:
r=|z|=√(√3)²+(-1)²
=2
x lies in 3rd quadrent
arg(z)=-Π+alpha
tan alpha=|y/x|
=√3
=tanΠ/3
alpha=Π/3
therefore arg(z) =-Π+Π/3
=-2Π/3
the argument is -2Π/3
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