Find the argument of -3V2 + 3/2 i
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Answer:
here's your answer
Step-by-step explanation:
Given,
z=
3
+i
2
modulus ∣z∣=
(
3
)
2
+(
2
)
2
=
5
argument θ=tan
−1
(
3
2
)⇒θ=39.23
∘
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