*Find the argument of: z = 1 + i√3*
1️⃣ π/3
2️⃣ 2π/3
3️⃣ π/6
4️⃣ none
Answers
Answered by
1
Answer:
Correct option is
C
4
3π
Given, z=−3+3i
⇒z=3(−1+i)
=3(
2
−1
+
2
i
)
=3
2
(cos(
4
3π
)+isin(
4
3π
))
=3
2
e
i
4
3π
Hence, principal argument of z is
4
3π
.
Answered by
0
Answer:
3 Is the answer ok bye afjwtwtjf211f2rhr
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