Question

find the arithmetic mean between (x+y)^2 and (x-y)^2​

Answer 1

Answer:

A.M. = [(x+y)² + (x-y)²]/2

=> [x²+y²+2xy+x²+y²-2xy] / 2

=> 2 ( x² + y² ) / 2

=> x² + y²

Answer 2

Answer:

x^2+y^2

Step-by-step explanation:

(x+y)^2 = x^2+y^2+2xy and (x-y)^2 = x^2+y^2-2xy.

Two terms are given initially therefore no.of observations = 2

Arithmetic mean= x^2+y^2+2xy+x^2+y^2-2xy/2

=> 2x^2+2y^2/2

=> 2(x^2+y^2)/2

=> x^2+y^2.............. is ur answer

hope this will help.....