Find the arithmetic mean,median and mode of the following data
class interval frequency
0-9 8
10-19 10
20-29 15
30-39 20
40-49 15
50-59 10
60-69 8
Answers
Answered by
0
Explanation:
Median will lie between 39.5 - 49.5 as 50 comes between 40-70
Median = 39.5 + 10 * ( 50 - 40)/30
= 39.5 + 3.33
= 42.83
Mode will lie in 39.5 - 49.5 as maximum frequency = 30
Mode = 39.5 + 10 * (30 - 18)/(30 -18 + 30 - 16)
= 39.5 + 4.6
= 44.1
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Answered by
0
Mean- (5*8)+(15*10)+(25*15)+(35*20)+(45*15)+(55*10)+(65*8)
3010/(8+10+15+20+15+10+8)
3010/86
35
3010/(8+10+15+20+15+10+8)
3010/86
35
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