find the arithmetic progression whose third term is 16 and the 7th term exceeds the 5th term by 12
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a +2d =16
t7 -t5 =12
a + 6d -(a +4d)=12
a + 6d - a - 4d =12
2d =12
d =6...
a +2d =16
a +12 =16
a = 4.
Ap = 4, 10,16
t7 -t5 =12
a + 6d -(a +4d)=12
a + 6d - a - 4d =12
2d =12
d =6...
a +2d =16
a +12 =16
a = 4.
Ap = 4, 10,16
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