find the arithmetic sequence whose 34th term is -39 and whose 50th term is -71?
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Answer:
Given:-
34th term = -39
50th term = -71
a+33d = -39 _______eq.1
a+49d = -71 ________eq.2
(balancing equation 1 and 2)
multipy eq.2 with -1
a+33d = -39
(a+49d = -71) ×-1
-a-49d = 71
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a-a+33d-49d = -39+71
-16d = 32
d=32/-16
d= -2
putting the value of d in equation 1.
a+33d = -39
a+33×-2 = -39
a-66 = -39
a=-39+66
a=27
Now, a=27 and d= -2
Thus,arithmetic sequence:-
a+d=27+(-2)=25
a+2d=27+(2×-2)=23
a+3d=27+(3×-2)=21
a+4d=27+(4×-2)=19
:-25,23,21,19,...
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