Question

Find the arra of region bounded by x=4 ,x+y=6 and the coordinate axes

Answer 1

Answer:y value will be 2

Step-by-step explanationy :

Answer 2

Question:- Find the area (in unit square) of region bounded by x = 4, x + y = 6 and coordinate axes​.

According to the question;

x = 4; x + y = 6 from these two equation we can say y = 2.

x = 4, x + y = 6,x=0 , y=0 are the four boundary for the region.

Let the line x + y = 6 intersect x = 4 at point B and it intersects y-axis at D.

The Coordinate of B is (4,2)

The Coordinate of D is (0,6).

O is the point representing(0,0).

Line x = 4 intersects x-axis at A(4,0).

⇒ area of OABD = area of OABC + area of BCD

⇒ $\frac{1}{2}$ × OA × AB + $\frac{1}{2}$ × BC × CD

⇒ $\frac{1}{2}$ × 4×2 + $\frac{1}{2}$×4×4

⇒ 8+8

⇒ 16 unit square.

The area (in unit square) of region bounded by x = 4, x + y = 6 and coordinate axes​ are 16 unit square.

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