Question

find the arthematic progression whose nth is 3n-5?
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Answer 1

Answer:

The A.P is -2, 1, 4, 7.....

Answer 2

$\huge{</strong><strong> \mathtt{ \fbox{Solution :)}}}$

Given ,

The general formula of AP is 3n-5

Thus ,

First term = 3(1) - 5 = -2

Second term = 3(2) - 5 = 1

Third term = 3(3) - 5 = 4

Forth term = 3(4) - 5 = 7

$\huge{ \large \mathtt{ \fbox{ </p><p>Verification :)}}}$

We know that , the difference b/w any two consecutive term of an AP is same or constant

Thus ,

1 - (-2) = 3 , 4 - 1 = 3

and

7 - 4 = 3

Hence verified

Therefore , the AP is -2 , 1 , 4 , 7

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