find the arthemetical mean of first "n" natural number whose frequency are equal to corresponding numbers .
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Let S be the required sum.
Therefore, S = 1 + 2 + 3 + 4 + 5 + .................... + n
Clearly, it is an Arithmetic Progression whose first term = 1, common difference = 1 and number of terms = n.
Therefore, S = n/2(2a+(n-1)d)
S=n/2(2+n-1)
S=n/2(n+1)
Therefore, S = 1 + 2 + 3 + 4 + 5 + .................... + n
Clearly, it is an Arithmetic Progression whose first term = 1, common difference = 1 and number of terms = n.
Therefore, S = n/2(2a+(n-1)d)
S=n/2(2+n-1)
S=n/2(n+1)
angelrathore:
answer is 2n+1/3
How
don't know yrr that's why I post the question
Where did I get the question and answer
Not I but you
i already uploaded the answer before so how u dont know @angelrathore
And darwin u can refer my answer
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Good question
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