Question

Find the arthmetic progression in which the third tern is 14 and sixth term is 26

Answer 1

Answer:

I think the question is half

Step-by-step explanation:

t3=14

t6=26

14=a+(n-1)d

26=a+(n-1)d

Answer 2

Step-by-step explanation:

Given: α3=14 , α6=26.

α3=α+2d=14(1)

α6=α+5d=26(2)

(2)-(1)

α+5d=26

(-)α+(-)2d=(-)14

3d=12

d=4.(3)

(3) in(1)

α+2*4=14

α=14-8=6.

α2=α+d=6+4=10.

The AP is 6 , 10 , 14.....

hope helps u.