find the asymptotes of the curve y = 4xe^-x^2
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Step-by-step explanation:
y=4xe−x2
⇒dydx=4e−x2−8x2e−x2
dydx=0⇒4e−x2−8x2e−x2=0⇒x=±12√
The function has a global maximum at x=12√ and a global minimum at x=−12√
The value of the function at the maximum and minimum are 22–√e−12and−22–√e
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