Question

find the asymptotes of the curve y = 4xe^-x^2

Answer 1

Step-by-step explanation:

y=4xe−x2

⇒dydx=4e−x2−8x2e−x2

dydx=0⇒4e−x2−8x2e−x2=0⇒x=±12√

The function has a global maximum at x=12√ and a global minimum at x=−12√

The value of the function at the maximum and minimum are 22–√e−12and−22–√e