Question

find the average frictional force needed to stop a car weighing 500 kg in a distance of 25 metre if the initial speed is 72 kilometre per hour ​

Answer 1

Answer:

initial speed= 72km/h=20 m/s

according to the third equation of motion,

v^2=u^2+2as

0= (20)^2+2×a×25

-400=50a

a= -400/50

a= -8m/s

force=ma

F= 500×(-8)

F= -4000N

but frictional force is always opposite so required frictional force is 4000N

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