Question

find the average frictional force that would stop a car of weight 500kg. in a distance of 25m its intial speed is 20m/s
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Answer 1

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Explanation:

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Answer 2

Answer:

Given -

Weight of car = 500 kg

Distance = 25 m

Speed = 20 m/s

To Find -

The average frictional force

Solution -

= 72×518 [Changing into m/s]

= 20 m/s.

Distance covered by it = 25 m.

${v}^{2} - {v}^{2} = 2as$

$= 0 - (20) ^{2} = 2(a)(25)$

$= - 400 = 50 \times a$

$a = - 8$

Now, Frictional Force = m × a

= 500×−8

= - 4000 N.

Here, negative sign shows the force is acting in the opposite direction of the displacement.

∴ Frictional force is 4000 N.

Thank You

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