Question

find the average frictional force that would stop a car of weight 500kg. in a distance of 25m its intial speed is 20m/s
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Answer 1

Answer:

Mass(m) = 500 kg.

Speed = 72

hr

km

= 72×518 [Changing into m/s]

= 20 m/s.

Distance covered by it = 25 m.

∵ v

²

−u

²

=2aS

⇒ 0−(20)

²

= 2(a)(25)

⇒ -400 = 50×a

⇒ a = - 8

s

2

m

Now, Frictional Force = m × a

= 500×−8

= - 4000 N.

Here, negative sign shows the force is acting in the opposite direction of the displacement.

∴ Frictional force is 4000 N.

Explanation:

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