Find the average number of key comparisons made by binary search
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U should elaborate the question
Anonymous:
the average number of key comparisons in binary search is (n-1)
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ts 2.9 on average; the question asked average number of comparisons on binary search; so as per algo first the middle, then since it is sorted while computing for the middle and equating to it at the same time it is determined which way to go further left or right;
1 2 3 4 5 6 7 8 9 10
For 5: 1
For 2,8 : on second comaprison, i.e., 2
And similarly
For 1,3,6,9: 3
And for 4,7,10: 4
compute it:1×1+2×2+4×3+3×410=2.9
1 2 3 4 5 6 7 8 9 10
For 5: 1
For 2,8 : on second comaprison, i.e., 2
And similarly
For 1,3,6,9: 3
And for 4,7,10: 4
compute it:1×1+2×2+4×3+3×410=2.9
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