Find the average of 1/10,2/10,3/10,4/10,5/10
Answers
Answer:
The average of \dfrac{2}{10} ,\dfrac{5}{10},\dfrac{6}{10},\dfrac{7}{10}102,105,106,107 and \dfrac{8}{10}108 = \dfrac{14}{25}2514
Step-by-step explanation:
The given numbers are:
\dfrac{2}{10} ,\dfrac{5}{10},\dfrac{6}{10},\dfrac{7}{10}102,105,106,107 and \dfrac{8}{10}108
Here, number of observations = 5
To find, the average of \dfrac{2}{10} ,\dfrac{5}{10},\dfrac{6}{10},\dfrac{7}{10}102,105,106,107 and \dfrac{8}{10}108 = ?
We know that,
Average = \dfrac{Sum of observations}{Numbers of observations}NumbersofobservationsSumofobservations
= \dfrac{1}{5}(\dfrac{2}{10}+\dfrac{5}{10}+\dfrac{6}{10}+\dfrac{7}{10}+\dfrac{8}{10})51(102+105+106+107+108)
= \dfrac{1}{5}(\dfrac{2+5+6+7+8}{10})51(102+5+6+7+8)
= \dfrac{1}{5}(\dfrac{2+5+6+7+8}{10})51(102+5+6+7+8)
= \dfrac{28}{50}5028
Didiving numerator and denominator by 2, we get
= \dfrac{\dfrac{28}{2} }{\dfrac{50}{2}}250228
= \dfrac{14}{25}2514
∴ The average of \dfrac{2}{10} ,\dfrac{5}{10},\dfrac{6}{10},\dfrac{7}{10}102,105,106,107 and \dfrac{8}{10}108 = \dfrac{14}{25}2514
Thus, the average of \dfrac{2}{10} ,\dfrac{5}{10},\dfrac{6}{10},\dfrac{7}{10}102,105,106,107 and \dfrac{8}{10}108 is equal to \dfrac{14}{25}2514 .