Math, asked by shivi97, 1 year ago

find the average of 1 upon 2, 1 upon 3,1 upon 4, 1 upon 6

Answers

Answered by arjun08
31
So, the question is

 \frac{1}{2} + \frac{1}{3} + \frac{1}{4} + \frac{1}{6}
On taking the L.C.M.
We get,

12 as the L.C.M.

So, then

 \frac{6 + 4 + 3 + 2}{12}
On adding up,

 \frac{15}{12}
So, the answer is 5/4

Since there were 4 fractions

So, the average is

=》5/4/4

=》5/4×4

=》5/16

Hope it helps you.

arjun08: plz mark me as brainliest
Answered by harendrachoubay
17

The  average of\dfrac{1}{2} ,\dfrac{1}{3} ,\dfrac{1}{4} and \dfrac{1}{6} is \dfrac{5}{16}.

Step-by-step explanation:

We have,

\dfrac{1}{2} ,\dfrac{1}{3} ,\dfrac{1}{4} and \dfrac{1}{6}

To find, the average = ?

We know that,

Average = \dfrac{Sum of all observations}{Total number of observations}

∴ Average = \dfrac{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+\dfrac{1}{6}}{4}

The LCM of 2, 3, 4 and 6 is 12.

= \dfrac{\dfrac{6+4+3+2}{12}}{4}

= \dfrac{\dfrac{15}{12}}{4}

= \dfrac{\dfrac{5}{4}}{4}=\dfrac{5}{16}

Hence, the  average of \dfrac{1}{2} ,\dfrac{1}{3} ,\dfrac{1}{4} and \dfrac{1}{6} is \dfrac{5}{16}.

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