Math, asked by kanishkathakur24, 19 days ago

find the average of 16/3 . 7/2. 9/2. 4/1​

Answers

Answered by sheeb12ansari
0

Given: The rational numbers\frac{16}{3},\frac{7}{2}  ,\frac{9}{2},\frac{4}{1}  .

We have to find the average of the given numbers\frac{16}{3},\frac{7}{2}  ,\frac{9}{2},\frac{4}{1}  .

For this, we will add all the given numbers, and then we will divide the total by4.

Then we will get the average number of the given values.

We are solving in the following way:

We have\frac{16}{3},\frac{7}{2}  ,\frac{9}{2},\frac{4}{1}  .

Now,

=>\frac{16}{3} +\frac{7}{2} +\frac{9}{2} +\frac{4}{1} \\\\=>\frac{52}{3}

Then,

=>\frac{52}{3} \times \frac{1}{4} \\\\=>\frac{13}{3} \\\\=>4.33

We get Average=4.33

Hence, the average of the given values will be\frac{13}{3} or 4.33.

Answered by divyapakhare468
0

To find : average of   \frac{16}{3} ,\frac{7}{2} ,\frac{9}{2}, \frac{4}{1}

Given data :  \frac{16}{3} ,\frac{7}{2} ,\frac{9}{2}, \frac{4}{1}

Solution :

  • To find average of given data wee have formula :

       Average =   sum of observations

                          total number of observations

  • to find sum of given observations we  need to equalize denominators by taking LCM.
  • LCM = 6
  • Now by multiplying the numerators by the same numbers as multiplied by denominator to make LCM
  • We get,   \frac{32}{6}, \frac{21}{6}, \frac{27}{6}, \frac{24}{6}
  • sum of observations = \frac{32 + 21+ 27 + 24}{6}

                                           = \frac{104}{6}

                                           = 84

  • Number of observations = 4
  • Average   = \frac{84}{4}

                         = 21

     Hence , average of given data is 21.

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