Find the average of 32(5) 53(10) 21(5) 77(10)
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= 32/5 + 53/10 + 21/5 + 77/10
= ( 64 + 53 + 42 + 77 ) / 10
= 236/10 ---( 1 )
Number of terms = 4
Mean = ( 1 ) / ( 2 )
= ( 236 / 10 ) / 4
= ( 236 ) / ( 10 × 4 )
= 59/10
= 5.9
Therefore ,
Required mean = 5.9
I hope this helps you.
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