Question

find the average of 4¹/6,1⅓,5/12,7/9,and 5/4​

Answer 1

Answer:

$\frac{143}{90}$

Step-by-step explanation:

$\frac{4 \frac{1}{6} +1 \frac{1}{3} + \frac{5}{12} + \frac{7}{9} + \frac{5}{4} }{5}$

$\frac{ \frac{25}{6} + \frac{4}{3} + \frac{5}{12} + \frac{7}{9} + \frac{5}{4} }{5}$

$\frac{ \frac{150 + 48 + 15 + 28 + 45}{36} }{5}$

$\frac{ \frac{286}{36} }{5}$

$\frac{ \frac{286}{36} }{5}$

$\frac{286}{36 \times 5}$

$\frac{286}{180}$

$= \frac{143}{90}$