Question

find the average of 6 numbers if the sum of first four is 40 and the sum of other two is 56

Answer 1

Let the numbers be a,b,c,d,e,f

The average = (a+b+c+d+e+f)/6

a+b+c+d  = 40

e+f = 56

Therefore a+b+c+d+e+f = 40+56 = 96

Average = 96/6 = 16

Answer 2

The average of 6 numbers = 16

To find:

the average of 6 numbers = ?

Given data:

the sum of first four numbers = 40

the sum of other two numbers = 56

Formula:

$average=\frac{\text { sum of the terms }}{\text { number of terms }}$

Solution:

$=\frac{\text { sum of the terms }}{\text { number of terms }}$

and let six numbers be a,b,c,d,e,f, then average equals

= $\frac{ a + b + c + d + e + f }{6}$

we already know that the sum of first four numbers = 40 and the sum of other two numbers = 56

by substituting we get,

= [56 + 40]÷6

= 96÷6

= 16

To solve more:

1. The sum of five numbers is 260.The average of first two numbers is 30 and the average of last two numbers is70. What is the third number?

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2. How can you identify the average, sum and count of number available in a given cell range without using the built-in function?

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