Find the average of all even numbers from 200 to 500?
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it's too hard to find the average.
take even number of 200 to 300 , 301 to 400 , and 401 to 500.
write even number and find average.
take even number of 200 to 300 , 301 to 400 , and 401 to 500.
write even number and find average.
Answered by
2
The even numbers from 200 to 500 also include 200. Therefore, the total number of even numbers in this case is (500-200)/2 +1 = 151
[+1 because we have subtracted 200 but it is also present in the series].
Now, this series of even numbers i.e., 200, 202,..., 500 is in arithmatic progression or in other words, the difference of two consecutive numbers is always 2. Hence, the middle term or this series is the average. Middle term is 76th even number starting from 200.
Thus, average =200 + 2×(76-1) =200+150 =350. [Answer]
Comment or message me for more, if needed. You can report this answer or notify me if somthing wrong found with this answer. Thanks!
[+1 because we have subtracted 200 but it is also present in the series].
Now, this series of even numbers i.e., 200, 202,..., 500 is in arithmatic progression or in other words, the difference of two consecutive numbers is always 2. Hence, the middle term or this series is the average. Middle term is 76th even number starting from 200.
Thus, average =200 + 2×(76-1) =200+150 =350. [Answer]
Comment or message me for more, if needed. You can report this answer or notify me if somthing wrong found with this answer. Thanks!
AmrendraOraon:
But, most simple result is, "The average of a arithmetic sequence is the average of first and last term". And, according to this the average comes to be (200+500)/2 =350
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