Find the average of cubes of 1, 3, 5, 7 and 9?
Answers
Answered by
1
Answer:1225
Step-by-step explanation:
(1*1*1)+(3*3*3)+(5*5*5)+(7*7*7)+(9*9*9)
=1+27+125+343+729
=1225
Answered by
3
cube of 1=1
cube of 3= 27
cube of 5= 125
cube of 7=343
cube of 9= 729
AVG=(1+27+125+343+729)/5
= 1225/5
=245
cube of 3= 27
cube of 5= 125
cube of 7=343
cube of 9= 729
AVG=(1+27+125+343+729)/5
= 1225/5
=245
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