find the average of first 10 multiple of 3
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Answer:
First 10 multiples of 3 are 3,6,9,12,30. This is an AP with a=3, n=10 and l=30. ∴ sum=n2(a+l)=102⋅(3+30)=165. ∴ mean,ˉx=16510=16.5.
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Step-by-step explanation:
multiple of 3=3,6,9,12,15,18,21,24,27,30. average of this numbers=(3+6+9+12+15+18+21+24+27+30)/10. average=165/10=16.5
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