Question

find the average of first 10 multiples of 8

Answer 1

The average would be -------

8+16+24+32+40+48+56+64+72+80/10
= 440/10
= 44

Answer 2

Hello dear!

Let us calculate the multiples of 8 first,
8*1 = 8
8*2 = 16
8*3 = 24
8*4 = 32
8*5 = 40
8*6 = 48
8*7 = 56
8*8 = 64
8*9 = 72
8*10 = 80

So the first ten multiples of 8 are 8,16,24,32,40,48,56,64,72 and 80.

The average of these multiples,
$\frac{8 + 16 + 24 + 32 + 40 + 48 + 56 + 64 + 72 + 80}{10}$
$\frac{440}{10}$


44

Your answer is 44.

Hope it helps!