Math, asked by sudersansuder03, 5 months ago

Find the average of first 11 multiples of 8 ?​

Answers

Answered by shivangidas2009
2

Answer:

Average of first 11 multiples of 8

= (8+16+24+32+40+48+56+64+72+80+88)

11

= 528

11

= 48

Answered by qwachieve
0

Given:

The first eleven multiples of 8 are  8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88.

To find:

We have to find the average of the first eleven multiples of 8.

Solution:

The average of numbers is the sum of the given numbers divided by the total count of the numbers.

The average is also termed as arithmetic mean or mean.

The formula for average is,

Average (arithmetic mean ) = \frac{Sum of all terms}{total number of terms}

Here, first 11 multiples of 8 are - 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88.

Average of first 11 multiples = (Sum of first eleven multiples of 8)/ Total number of the multiples.

Average of first 11 multiples = (8+16+24+32+40+48+56+64+72+ 80+ 88)/ 11

= 528 / 11

= 48

The average of the first 11 multiples of 8 is 48.

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