Question

Find the average of first 8multiple of 4

Answer 1

Answer:

4

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Answer 2

Answer:

Method I:

In the method of Arithmetic Progression (AP) :

AP:- 4,8,...,32

a = 4

d = 4

l = 32

n = 8

Sum of first n terms = n/2×[2a + (n-1) d]

= n/2×[a + l]

Sum of first 8 terms = (8/2) × (4 + 32) = 4 × 36

= 144

Average of first 8 terms = S_8/8 = 144/8 = 18

Method II:

Normal mean method:

Average = Σ n_i/8 , n = 1,2,...,8

= ( 4+8+12+16+20+24+28+32 )/8

= 144/8

= 18