Question

find the average of first ten consecutive numbers​

Answer 1

Answer:

Hence, average of n consecutive natural numbers is =  2a+(n−1)/2 .

Step-by-step explanation:

Since, the numbers in series are consecutive, we say common difference between them is d=1.

Then, by sum of AP series formula, S=  2a+(n−1)n/2  

Now, we know, mean of ‘n’ numbers=  (Sumof ' n ' numbers)/n  

Then, mean = S/n =  2a+(n−1)/2 .

Hence, average of n consecutive natural numbers is =  2a+(n−1)/2 .