Question

Find the average of n, n+2, n+4, n+6, n+8.
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Answer 1

Answer:

Average = Sum/Number of terms

=> (n + n + 2 + n + 4 + n + 6 + n + 8)/5

=> (5n + 20)/5

=> 5(n + 4)/5

=> n + 4

_____________

Simpler method:

When the terms odd in number:

Middle term = (n + 1)/2

Here, n = 5

=> (n + 1)/2 = 6/2 = 3

3rd term is = n + 4

Verified ✔

When the terms are even in number:

Middle term = n/2

_____________

Answer 2

$\frac{(5n+21)}{5}$ is the average of given questions

Step-by-step explanation

Average of digits or number is defined as the sum of all digits or numbers divide by total digits or number.

so average= $\frac{n+(n+2)+(n+4)+(n+6)+(n+8)}{5}$

    average= $\frac{n+n+n+n+n+2+4+6+8}{5}$

    average= $\frac{(5n+21)}{5}$

is the average of given data.