Question

Find the average of square of first 5 consecutive natural numbers.

Answer 1

first five consecutive natural numbers are

$\mathcal\red{1,2,3,4,5,}$

$average = \frac{a + b + c + d + e}{2}$

$average = \frac{1 + 2 + 3 + 4 + 5}{2}$

$average = \frac{15}{2}$

$average = \small\purple{7.5}$

Answer 2

Given:

First 5 consecutive natural numbers.

To Find:

The average of square of first 5 consecutive natural numbers.

Solution:

The first five consecutive natural numbers are,

1, 2, 3, 4, and 5.

1^2 = 1.

2^2 = 4.

3^2 = 9.

4^2 = 16.

5^2 = 25.

Now, the average of the first five consecutive natural numbers are

= (1 + 4 + 9 + 16 + 25) / 5.

= 55 / 5.

= 11.

Hence, the average of the first five consecutive natural numbers is 11.