Math, asked by bilalbhat2021, 7 months ago

find the average of squares of consecutive odd numbers from 1 to11.

Answers

Answered by divyanoorsharmajp

0

Answer:

47.6666666667

Step-by-step explanation:

$1^{2}+3^{2}+5^{2}+7^{2}+9^{2}+11^{2}$ /6

=1+9+25+49+81+121/6

=286/6

=143/3

= 47 $\frac{2}{3}$ or 47.6666666667

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