Question

Find the average of the first 56 natural numbers

Answer 1

Answer:Ans: 28.5 (28.1/2)

Method 1: We can Add All natural numbers from 1 to 56 and than divide that sum by the number of original numbers (here its 56) to get the average.. Arithmetic Progression divide by the number of natural numbers present in the Q… ie: (1+2+3+4+….+56) ÷ 56.. To give the Average. It's time consuming but does give the correct answer.. Here it comes to (1596÷56)=28.5

Methid 2 : use Gauss’s formula [(n^2)+n]÷2, it gives the sum of all natural numbers between 1 & ‘n’..

In this, Q, ‘n’ = the last number which is 56.

So once you plug 56 where ’n’ is, you get

[(56^2)+56]÷2 = 1596 is. Sum of all natural numbers between 1&56.

Now to get the Average if that, divide that sum by number of Natural numbers present. Ie. (1596÷56)=28.5

Step-by-step explanation:

Answer 2

Answer:

28.5

Step-by-step explanation:

Sum of first 56 numbers = $\frac{56*57}{2}$ = 1596

Average = $\frac{1596}{56}$ = 28.5