find the average of the first 6 odd number and the average of first 6 even numbers then find the difference between the two average
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Since the numbers are odd, I will take the first number of the 6 consecutive odd numbers as (n+1).
Given:
((n+1)+(n+3)+(n+5)+(n+7)+(n+9)+(n+11)) / 6 = 20
6n+36= 120
6n = 84
n= 14
So the first number in the series of the 6 consecutive odd number is (n+1) = 14+1 = 15 and the last / largest of the number is (14+11) = 25.
25 is the answer!
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