Question

Find the average of the numbers.

(a). 2, 3, 5, 7, 11

(b). 5⅓, 3½, 4½, 4

pl pl pl answer fast

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Answer 1

$\large\boxed{{Question:-}}$

Find the average of the numbers.

$Find \: the \: average \: of \: the \: numbers. </p><p>$

$(a) \: 2, 3,5,7,11$

$(b) \: 5 \dfrac{1}{3} ,3 \dfrac{1}{2},4 \dfrac{1}{2} ,4$

$\large\boxed{{Solution:-}}$

$(a) \: \:Sum \: of \: the \: given \: numbers = (2 + 3 + 5 + 7 + 11) = 28$

$Number \: of \: these \: numbers = 5$

$Average \: of \: the \: given \: numbers = \frac{ Sum \: of \: given \: numbers }{ Number \: of \: these \: numbers } \\ = \frac{28}{5} = 5.6$

$Hence, the \: average \: of \: the \: given \: numbers \: is \: 5.6$

$(b)The \: given \: numbers \: are \: \frac{16}{3}, \frac{7}{2} , \frac{9}{2} \: and \: 4$

$Sum \: of \: the \: given \: numbers = ( \frac{16}{3} + \frac{7}{2} + \frac{9}{2} + \frac{4}{1} ) \\ = ( \frac{32 + 21 + 27 + 24}{6} ) = \frac{104}{6} = \frac{52}{3}$

$Number \: of \: these \: numbers = 4$

$Average \: of \: these \: numbers = ( \frac{52}{3} \div 4) = ( \frac{52}{3} \times \frac{1}{4} ) = \frac{13}{3} =4 \frac{1}{3}$

$Hence, the \: average \: of \: the \: given \: numbers \: is \: 4 \frac{1}{3}$

$\large\boxed{{Extra\: information:-}}$

• $Average = \frac{sum \: of \: the \: given \: numbers}{number \: of \: observations}$
• $Average \: of \: given \: numbers = \frac{sum \: of \: the \: given \: numbers}{numbers \: of \: these \: numbers}$

Answer 2

$\huge{ \underline{ \bold{ᴀɴsᴡᴇʀ....{ \heartsuit}}}}$

(a)Sumofthegivennumbers=(2+3+5+7+11)=28

Number \: of \: these \: numbers = 5Numberofthesenumbers=5

$$\begin{lgathered}Average \: of \: the \: given \: numbers = \frac{ Sum \: of \: given \: numbers }{ Number \: of \: these \: numbers } \\ = \frac{28}{5} = 5.6\end{lgathered}$$

$$Hence, the \: average \: of \: the \: given \: numbers \: is \: 5.6$$

$$(b)The \: given \: numbers \: are \: \frac{16}{3}, \frac{7}{2} , \frac{9}{2} \: and \: 4$$

$$\begin{lgathered}Sum \: of \: the \: given \: numbers = ( \frac{16}{3} + \frac{7}{2} + \frac{9}{2} + \frac{4}{1} ) \\ = ( \frac{32 + 21 + 27 + 24}{6} ) = \frac{104}{6} = \frac{52}{3}\end{lgathered}$$

$$Number \: of \: these \: numbers = 4$$

$$Average \: of \: these \: numbers = ( \frac{52}{3} \div 4) = ( \frac{52}{3} \times \frac{1}{4} ) = \frac{13}{3} =4 \frac{1}{3}$$

$$Hence, the \: average \: of \: the \: given \: numbers \: is \: 4 \frac{1}{3}$$

$$\large\boxed{{Extra\: information:-}}$$

$$Average = \frac{sum \: of \: the \: given \: numbers}{number \: of \: observations}$$

$$Average \: of \: given \: numbers = \frac{sum \: of \: the \: given \: numbers}{numbers \: of \: these \: numbers}$$