Question

Find the average power delivered by the weight of a projectile, when it is projected in air at some angle with horizontal. What is the instantaneous power delivered by weight of projectile zero?

Answer 1

Explanation:

let the angle of projection be ß and weight be object projected be W and is projected with a velocity v

instantaneous power = F.v

when pojected

= W × v × cos(90+ß)

= W × v × sinß

and average will be zero for the total motion as the velocity at the time of projection is equal to the velocity at the end of projection and thus KE is also same.

This implies that no net work is done on the object and, hence the power delivered must also be zero.

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Answer 2

Answer:

zero, at highest point of projection