Physics, asked by sriramsri8274, 6 months ago

Find the average resistance if volts is 4 and amp is 9.

Answers

Answered by Anonymous
102

Solution :—

Given :-

  • Volt (V) = 4
  • Ampere (I) = 9

To Find :-

  • Average Resistance (R)

Formula Used :-

  • Resistance (R) = Volt (V) / Ampere (I)

Therefore,

R = 4/9

Thus, the average resistance is 4/9

Answered by Yuseong
384

Question from chapter “Electricity”.

 \huge\rm\red { Question-}

Find the average resistance if volts is 4 and amp is 9.

How to solve?

  • Here, we are given that the current flowing is 9 Ampere or in other words Ampere is 9 and Volt is 4.
  • So, we can apply here the formula of ohm's law which is || V = IR || and can find the average resistance.
  • Let's solve‼

 \huge\rm\blue { Solution-}

Given-

  •  \sf\pink { V ( volt ) = 4 }

  •  \sf\pink { I ( Current ) = 9A}

Thus,

  •  \sf\pink { I ( Ampere ) = 9}

We have to find-

  •  \sf\blue { R (average \: resistance) }

Calculation-

We know that,

 {\huge {\boxed {\tt { V = IR } }}}

Where,

  •  \sf { V = volt = 4 }
  •  \sf { I = Current= 9A}
  •  \sf { R = Resistance = ? }

Now, put the values according to the formula-

 {\qquad {\underline {\underline  {\rm {\red { V = IR }}}}}}

 \sf { \qquad \leadsto 4 = 9 \times R }

 \sf { \qquad \leadsto 4 = 9R }

 \sf \red { \qquad \leadsto R = \dfrac{4}{9} Ω}

 \therefore The average resistance is 4/9 Ω.

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Additional Information-

Some important formulae-

  •  \sf { I = \dfrac{Q}{T} }

  •  \sf { V  = \dfrac{W}{Q} }

  •  \sf { V= IR } [ Ohm's law ]

  •  \sf { R = ρ \dfrac{L}{A} }

  •  \sf { R_s  = R_1 + R_2 + R_3.........}

  •  \sf {\dfrac{1}{ R_p  }= \dfrac{1}{ R_1 } +   \dfrac{1}{ R_2  }+ \dfrac{1}{ R_3  }.........}

Here,

Q is charge and its SI unit is Coulomb ( C ).

I is current and its SI unit is Ampere ( A ).

T is time and its SI unit is second ( S ).

V is potential difference and its SI unit is Volt ( V ).

W is work done and its SI unit is Joule ( J ).

R is resistance and its SI unit is Ohm ( Ω ).

ρ is resistivity and its SI unit is Ωm.

L is length and its SI unit is m.

A is cross sectional area and its SI unit is  \rm{ {m}^{2} }.

 \sf { R_s } is resistance in series combination.

 \sf { R_p } is resistance in parallel combination.

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