Physics, asked by singhshreya55748, 10 months ago

Find the average speed of a bicycle if it completes two rounds of a circular track of radius 140m twice in 5min52sec. ​

Answers

Answered by BrainlyIAS
10

Answer

  • Average Speed of the vehicle is 5 m/s

Given

  • A bicycle completes two rounds of a circular track of radius 140 m twice in 5 min 52 sec

To Find

  • The Average Speed

Solution

Average Speed is defined as " Total distance covered per total time "

Distance for Two rounds = 2 * ( 2πr)

⇒ Distance for Two rounds = 4π (140)

⇒ Distance for Two rounds = 560 π m

So , Total distance = 560 π m

Total time = 5 min 52 sec

⇒ Total time = 5(60) + 52 sec

Total time = 352 sec

So ,

\bf Average\ Speed\ =\dfrac{Total\ distance}{Total\ time}\\\\\implies \bf Average\ Speed\ = \dfrac{560\pi}{352}\\\\\implies \bf Average\ Speed\ = 5\ m/s

Answered by Anonymous
53

Qᴜᴇsᴛɪᴏɴ

➥ Find the average speed of a bicycle if it completes two rounds of a circular track of radius 140m twice in 5min 52sec.

Aɴsᴡᴇʀ

➥ Average speed of bicycle = 5 m/s

Gɪᴠᴇɴ

➤ Given track radius = 140m

➤ Total time = 5min 52 second

Tᴏ Fɪɴᴅ

➤ Average speed of bicycle = ?

\\

According To Given Question

\\

 \sf{Total  \: distance  \: covered = 2  \times  (2\pi r)} \\  \\  \sf{So  \: total  \: distance = 4 \times \pi \times 140} \\  \\  \sf{: \implies Total  \: distance = 4 \times  \frac{22}{ \cancel{ \: 7 \: }}  \times  \cancel{140}} \\  \\  \sf{: \implies Total  \: distance =4 \times 22 \times 20} \\  \\ \sf{: \implies Total  \: distance = 1760 \: m}

\\

 \sf{Total \:  time = 5min \:  352sec} \\  \\  \sf{:\implies Total \:  time = 5 \times 60 + 52} \\  \\  \sf{:\implies Total \: time =   352 \: sec}

Now,

❊ As we know that the formula for finding the Average speed is ፦

\bf{:\implies Average \:  speed =  \dfrac{Total \: distance}{Total \: time} }

⤵ On putting the given value in the formula, we get

\sf{:\implies Average \:  speed =  \frac{ \cancel{1760}}{ \cancel{352} }} \\  \\  \sf{ : \implies  Average \:speed = \underline{ \boxed{ \purple{ \bf{ \:  \:  5m/s \:  \: }}}}}

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