Question

Find the average speed of a bycycle if it completes two round of a circular track of radius 140m twice In 5 min 52 sec

A:10m/s
B:5m/s
C:2m/s
D:4m/s

Answer 1

♠♠ HOLA ♠♠

$\large{Ans .\: 5 m/s}$

$c \: = 2\pi \: r \\ c = 2 \times \frac{22}{7} \times 140 = 880 \\ 2 \: round \: \\ = 2 \times 880 = 1760 \: metres \: \\ \\ av. \: speed \: = \frac{s}{t} \\ = > \frac{1760}{352} = 5m {s}^{ - 1}$

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Answer 2

The average speed of the bicycle is 5 m/s.

Explanation:

Radius of the circular track, r = 140 m

Time, t = 5 min 52 sec = 352 s

On the circular path, distance covered by the bicycle is the is its circumference. So, speed is given by :

$v=\dfrac{2\times 2\pi r}{t}\\\\v=\dfrac{2\times 2\pi \times 140}{352}\\\\v=4.997\ m/s$

or

v = 5 m/s

So, the average speed of the bicycle is 5 m/s.

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