Question

Find the average translational kinetic energy per molecule if one mole of the gas is contained in a volume 1.23 to the power minus 3 m cube at a pressure of 2 into 10 to the power minus 5 newton per metre square avogadro number and moles

Answer 1

The average translational kinetic energy per molecule is 6.13 × 10⁻³² J

We know, according to kinetic theory of gases, Pressure P is given as:

P = (2/3) × (Avogadro No. × Moles × K.E ÷ Volume )

Given, P = 2×10⁻⁵ N/m

Volume = 1.23×10⁻³ m³

Avogadro Number = 6.023×10²³

Moles = 1

So, K.E. = (3 × Pressure × Volume ) / (2 × Avogadro no. × Moles)

Putting the respective values, we get:

K.E. = (3 × 2×10⁻⁵ ×  1.23×10⁻³ ) / (2 × 6.023×10²³ × 1)

      = 6.13 × 10⁻³² J