Find the average velocity of a moving object in a particular time interval along a given direction if it moves first 10 metres in 5 seconds and next 20 metres in 9 seconds. Please do not spam or else you will be reported
Answers
Answer :-
Average velocity of the moving object is 2.14 m/s .
Explanation :-
We have :-
→ 1st distance = 10 m
→ Time taken to cover 10 m = 5 sec
→ 2nd distance = 20 m
→ Time taken to cover 20 m = 9 sec
To find :-
→ Average velocity of the object.
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Since, the object is moving along a same direction, so it's displacement will be equal to the distance covered in two successive time intervals.
Total distance covered/displacement by the object :-
= (10 + 20) m
= 30 m
Total time taken :-
= (5 + 9) s
= 14 s
Average velocity :-
= Total displacement/Total time
= 30/14
= 2.14 m/s
Answer:
Given :-
- A particular time interval along a direction if it moves first 10 metres in 5 seconds and next 20 meters in 9 seconds.
To Find :-
- What is the average velocity of a moving object.
Formula Used :-
Average Velocity Formula :
Solution :-
First, we have to find the distance travelled by a moving object :
Given :
- First Distance (d₁) = 10 m
- Second Distance (d₂) = 20 m
Again, we have to find the total time taken by a moving object :
Given :
- First time (t₁) = 5 seconds
- Second time (t₂) = 9 seconds
Now, we have to find the average velocity :
Given :
- Distance Travelled = 30 m
- Total time taken = 14 seconds
According to the question by using the formula we get,
The average velocity of a moving object is 2.14 m/s.