Physics, asked by KingNipunDK, 1 year ago

Find the average velocity of a particle released from rest from a height of 125 m over a time interval till it strikes the ground.(Take g = 10m/s sq. )

Answers

Answered by pratyush4211

2

AVERAGe velocity= Total distance/Time
=125/5
=25 m/s

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KingNipunDK: Right answer

Answered by khanshahjahanhmt123

0

Answer:

Explanation:u= 0

H=125

g=10

V=

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