Question

Find the average velocity of a projectile during the time internal it crosses half of its makimum height u, <

Answer 1

i think 9.8 approx is the answer

Answer 2

Total of flight T = (2u sin⁡θ)/g

Average velocity = (change in displacement)/time

From the figure, it can be said AB is horizontal.


So there is no effect of vertical component of the velocity during this displacement.


So because the body moves at a constant speed of ‘u cos θ’ in horizontal direction.


The average velocity during this displacement will be u ‘cos θ ‘ in the horizontal direction.