Question

find the base angle of an isosceles triangle whose vertex angle is 130 degree.
pls and step by step..​

Answer 1

Answer:

Let each base angle be x in an isosceles △ABC

Then vertex angle be 2(x+x)=4x

Since sum of angles of a triangle is 180

o

.

Hence 4x+x+x=180

o

⇒6x=180

0

⇒x=30

0

∴ Angles are 30

o

,30

o

,120

o